+++ /dev/null
-// (C) Copyright Howard Hinnant
-// (C) Copyright 2010-2011 Vicente J. Botet Escriba
-// Use, modification and distribution are subject to the Boost Software License,
-// Version 1.0. (See accompanying file LICENSE_1_0.txt or copy at
-// http://www.boost.org/LICENSE_1_0.txt).
-
-//===-------------------------- locale ------------------------------------===//
-//
-// The LLVM Compiler Infrastructure
-//
-// This file is dual licensed under the MIT and the University of Illinois Open
-// Source Licenses. See LICENSE.TXT for details.
-//
-//===----------------------------------------------------------------------===//
-
-// This code was adapted by Vicente from Howard Hinnant's experimental work
-// on chrono i/o to Boost and some functions from libc++/locale to emulate the missing time_get::get()
-
-#ifndef BOOST_CHRONO_IO_TIME_POINT_IO_H
-#define BOOST_CHRONO_IO_TIME_POINT_IO_H
-
-#include <time.h>
-
-static int32_t is_leap(int32_t year) {
- if(year % 400 == 0)
- return 1;
- if(year % 100 == 0)
- return 0;
- if(year % 4 == 0)
- return 1;
- return 0;
-}
-
-static int32_t days_from_0(int32_t year) {
- year--;
- return 365 * year + (year / 400) - (year/100) + (year / 4);
-}
-
-int32_t static days_from_1970(int32_t year) {
- static const int days_from_0_to_1970 = days_from_0(1970);
- return days_from_0(year) - days_from_0_to_1970;
-}
-
-static int32_t days_from_1jan(int32_t year,int32_t month,int32_t day) {
- static const int32_t days[2][12] =
- {
- { 0,31,59,90,120,151,181,212,243,273,304,334},
- { 0,31,60,91,121,152,182,213,244,274,305,335}
- };
-
- return days[is_leap(year)][month-1] + day - 1;
-}
-
-static time_t internal_timegm(tm const *t) {
- int year = t->tm_year + 1900;
- int month = t->tm_mon;
- if(month > 11)
- {
- year += month/12;
- month %= 12;
- }
- else if(month < 0)
- {
- int years_diff = (-month + 11)/12;
- year -= years_diff;
- month+=12 * years_diff;
- }
- month++;
- int day = t->tm_mday;
- int day_of_year = days_from_1jan(year,month,day);
- int days_since_epoch = days_from_1970(year) + day_of_year ;
-
- time_t seconds_in_day = 3600 * 24;
- time_t result = seconds_in_day * days_since_epoch + 3600 * t->tm_hour + 60 * t->tm_min + t->tm_sec;
-
- return result;
-}
-
-#endif